Euler problem 48

The series, 1¹ + 2² + 3³ + ... + 10¹⁰ = 10405071317.

Find the last ten digits of the series, 1¹ + 2² + 3³ + ... + 1000¹⁰⁰⁰.

analyse:
Because only the last ten digits are needed in the answer we can avoid big integers by 
truncating each calculation to ten digits.

Problem48 =  9110846700 elapsed time:   18 ms. Test Passed.